Optimal. Leaf size=165 \[ -\frac {7 \sqrt {e \cot (c+d x)}}{8 a^3 d e (\cot (c+d x)+1)}-\frac {11 \tan ^{-1}\left (\frac {\sqrt {e \cot (c+d x)}}{\sqrt {e}}\right )}{8 a^3 d \sqrt {e}}-\frac {\tan ^{-1}\left (\frac {\sqrt {e}-\sqrt {e} \cot (c+d x)}{\sqrt {2} \sqrt {e \cot (c+d x)}}\right )}{2 \sqrt {2} a^3 d \sqrt {e}}-\frac {\sqrt {e \cot (c+d x)}}{4 a d e (a \cot (c+d x)+a)^2} \]
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Rubi [A] time = 0.65, antiderivative size = 165, normalized size of antiderivative = 1.00, number of steps used = 8, number of rules used = 7, integrand size = 25, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.280, Rules used = {3569, 3649, 3653, 3532, 205, 3634, 63} \[ -\frac {7 \sqrt {e \cot (c+d x)}}{8 a^3 d e (\cot (c+d x)+1)}-\frac {11 \tan ^{-1}\left (\frac {\sqrt {e \cot (c+d x)}}{\sqrt {e}}\right )}{8 a^3 d \sqrt {e}}-\frac {\tan ^{-1}\left (\frac {\sqrt {e}-\sqrt {e} \cot (c+d x)}{\sqrt {2} \sqrt {e \cot (c+d x)}}\right )}{2 \sqrt {2} a^3 d \sqrt {e}}-\frac {\sqrt {e \cot (c+d x)}}{4 a d e (a \cot (c+d x)+a)^2} \]
Antiderivative was successfully verified.
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Rule 63
Rule 205
Rule 3532
Rule 3569
Rule 3634
Rule 3649
Rule 3653
Rubi steps
\begin {align*} \int \frac {1}{\sqrt {e \cot (c+d x)} (a+a \cot (c+d x))^3} \, dx &=-\frac {\sqrt {e \cot (c+d x)}}{4 a d e (a+a \cot (c+d x))^2}-\frac {\int \frac {-\frac {7 a^2 e}{2}+2 a^2 e \cot (c+d x)-\frac {3}{2} a^2 e \cot ^2(c+d x)}{\sqrt {e \cot (c+d x)} (a+a \cot (c+d x))^2} \, dx}{4 a^3 e}\\ &=-\frac {7 \sqrt {e \cot (c+d x)}}{8 a^3 d e (1+\cot (c+d x))}-\frac {\sqrt {e \cot (c+d x)}}{4 a d e (a+a \cot (c+d x))^2}+\frac {\int \frac {\frac {7 a^4 e^2}{2}-4 a^4 e^2 \cot (c+d x)+\frac {7}{2} a^4 e^2 \cot ^2(c+d x)}{\sqrt {e \cot (c+d x)} (a+a \cot (c+d x))} \, dx}{8 a^6 e^2}\\ &=-\frac {7 \sqrt {e \cot (c+d x)}}{8 a^3 d e (1+\cot (c+d x))}-\frac {\sqrt {e \cot (c+d x)}}{4 a d e (a+a \cot (c+d x))^2}+\frac {11 \int \frac {1+\cot ^2(c+d x)}{\sqrt {e \cot (c+d x)} (a+a \cot (c+d x))} \, dx}{16 a^2}+\frac {\int \frac {-4 a^5 e^2-4 a^5 e^2 \cot (c+d x)}{\sqrt {e \cot (c+d x)}} \, dx}{16 a^8 e^2}\\ &=-\frac {7 \sqrt {e \cot (c+d x)}}{8 a^3 d e (1+\cot (c+d x))}-\frac {\sqrt {e \cot (c+d x)}}{4 a d e (a+a \cot (c+d x))^2}+\frac {11 \operatorname {Subst}\left (\int \frac {1}{\sqrt {-e x} (a-a x)} \, dx,x,-\cot (c+d x)\right )}{16 a^2 d}-\frac {\left (2 a^2 e^2\right ) \operatorname {Subst}\left (\int \frac {1}{-32 a^{10} e^4-e x^2} \, dx,x,\frac {-4 a^5 e^2+4 a^5 e^2 \cot (c+d x)}{\sqrt {e \cot (c+d x)}}\right )}{d}\\ &=-\frac {\tan ^{-1}\left (\frac {\sqrt {e}-\sqrt {e} \cot (c+d x)}{\sqrt {2} \sqrt {e \cot (c+d x)}}\right )}{2 \sqrt {2} a^3 d \sqrt {e}}-\frac {7 \sqrt {e \cot (c+d x)}}{8 a^3 d e (1+\cot (c+d x))}-\frac {\sqrt {e \cot (c+d x)}}{4 a d e (a+a \cot (c+d x))^2}-\frac {11 \operatorname {Subst}\left (\int \frac {1}{a+\frac {a x^2}{e}} \, dx,x,\sqrt {e \cot (c+d x)}\right )}{8 a^2 d e}\\ &=-\frac {11 \tan ^{-1}\left (\frac {\sqrt {e \cot (c+d x)}}{\sqrt {e}}\right )}{8 a^3 d \sqrt {e}}-\frac {\tan ^{-1}\left (\frac {\sqrt {e}-\sqrt {e} \cot (c+d x)}{\sqrt {2} \sqrt {e \cot (c+d x)}}\right )}{2 \sqrt {2} a^3 d \sqrt {e}}-\frac {7 \sqrt {e \cot (c+d x)}}{8 a^3 d e (1+\cot (c+d x))}-\frac {\sqrt {e \cot (c+d x)}}{4 a d e (a+a \cot (c+d x))^2}\\ \end {align*}
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Mathematica [A] time = 1.27, size = 217, normalized size = 1.32 \[ \frac {\sqrt {\cot (c+d x)} \left (-9 \sqrt {\cot (c+d x)}+9 \cos (2 (c+d x)) \sqrt {\cot (c+d x)}-7 \sin (2 (c+d x)) \sqrt {\cot (c+d x)}-22 \tan ^{-1}\left (\sqrt {\cot (c+d x)}\right )-22 \sin (2 (c+d x)) \tan ^{-1}\left (\sqrt {\cot (c+d x)}\right )-4 \sqrt {2} (\sin (c+d x)+\cos (c+d x))^2 \tan ^{-1}\left (1-\sqrt {2} \sqrt {\cot (c+d x)}\right )+4 \sqrt {2} (\sin (c+d x)+\cos (c+d x))^2 \tan ^{-1}\left (\sqrt {2} \sqrt {\cot (c+d x)}+1\right )\right )}{16 a^3 d \sqrt {e \cot (c+d x)} (\sin (c+d x)+\cos (c+d x))^2} \]
Antiderivative was successfully verified.
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fricas [A] time = 0.45, size = 504, normalized size = 3.05 \[ \left [-\frac {2 \, \sqrt {2} \sqrt {-e} {\left (\sin \left (2 \, d x + 2 \, c\right ) + 1\right )} \log \left (-\sqrt {2} \sqrt {-e} \sqrt {\frac {e \cos \left (2 \, d x + 2 \, c\right ) + e}{\sin \left (2 \, d x + 2 \, c\right )}} {\left (\cos \left (2 \, d x + 2 \, c\right ) + \sin \left (2 \, d x + 2 \, c\right ) - 1\right )} - 2 \, e \sin \left (2 \, d x + 2 \, c\right ) + e\right ) + 11 \, \sqrt {-e} {\left (\sin \left (2 \, d x + 2 \, c\right ) + 1\right )} \log \left (\frac {e \cos \left (2 \, d x + 2 \, c\right ) - e \sin \left (2 \, d x + 2 \, c\right ) + 2 \, \sqrt {-e} \sqrt {\frac {e \cos \left (2 \, d x + 2 \, c\right ) + e}{\sin \left (2 \, d x + 2 \, c\right )}} \sin \left (2 \, d x + 2 \, c\right ) + e}{\cos \left (2 \, d x + 2 \, c\right ) + \sin \left (2 \, d x + 2 \, c\right ) + 1}\right ) - \sqrt {\frac {e \cos \left (2 \, d x + 2 \, c\right ) + e}{\sin \left (2 \, d x + 2 \, c\right )}} {\left (9 \, \cos \left (2 \, d x + 2 \, c\right ) - 7 \, \sin \left (2 \, d x + 2 \, c\right ) - 9\right )}}{16 \, {\left (a^{3} d e \sin \left (2 \, d x + 2 \, c\right ) + a^{3} d e\right )}}, -\frac {4 \, \sqrt {2} \sqrt {e} {\left (\sin \left (2 \, d x + 2 \, c\right ) + 1\right )} \arctan \left (-\frac {\sqrt {2} \sqrt {e} \sqrt {\frac {e \cos \left (2 \, d x + 2 \, c\right ) + e}{\sin \left (2 \, d x + 2 \, c\right )}} {\left (\cos \left (2 \, d x + 2 \, c\right ) - \sin \left (2 \, d x + 2 \, c\right ) + 1\right )}}{2 \, {\left (e \cos \left (2 \, d x + 2 \, c\right ) + e\right )}}\right ) + 22 \, \sqrt {e} {\left (\sin \left (2 \, d x + 2 \, c\right ) + 1\right )} \arctan \left (\frac {\sqrt {\frac {e \cos \left (2 \, d x + 2 \, c\right ) + e}{\sin \left (2 \, d x + 2 \, c\right )}}}{\sqrt {e}}\right ) - \sqrt {\frac {e \cos \left (2 \, d x + 2 \, c\right ) + e}{\sin \left (2 \, d x + 2 \, c\right )}} {\left (9 \, \cos \left (2 \, d x + 2 \, c\right ) - 7 \, \sin \left (2 \, d x + 2 \, c\right ) - 9\right )}}{16 \, {\left (a^{3} d e \sin \left (2 \, d x + 2 \, c\right ) + a^{3} d e\right )}}\right ] \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {1}{{\left (a \cot \left (d x + c\right ) + a\right )}^{3} \sqrt {e \cot \left (d x + c\right )}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [B] time = 0.83, size = 426, normalized size = 2.58 \[ -\frac {7 \left (e \cot \left (d x +c \right )\right )^{\frac {3}{2}}}{8 d \,a^{3} \left (e \cot \left (d x +c \right )+e \right )^{2}}-\frac {9 e \sqrt {e \cot \left (d x +c \right )}}{8 d \,a^{3} \left (e \cot \left (d x +c \right )+e \right )^{2}}-\frac {11 \arctan \left (\frac {\sqrt {e \cot \left (d x +c \right )}}{\sqrt {e}}\right )}{8 a^{3} d \sqrt {e}}+\frac {\left (e^{2}\right )^{\frac {1}{4}} \sqrt {2}\, \ln \left (\frac {e \cot \left (d x +c \right )+\left (e^{2}\right )^{\frac {1}{4}} \sqrt {e \cot \left (d x +c \right )}\, \sqrt {2}+\sqrt {e^{2}}}{e \cot \left (d x +c \right )-\left (e^{2}\right )^{\frac {1}{4}} \sqrt {e \cot \left (d x +c \right )}\, \sqrt {2}+\sqrt {e^{2}}}\right )}{16 d \,a^{3} e}+\frac {\left (e^{2}\right )^{\frac {1}{4}} \sqrt {2}\, \arctan \left (\frac {\sqrt {2}\, \sqrt {e \cot \left (d x +c \right )}}{\left (e^{2}\right )^{\frac {1}{4}}}+1\right )}{8 d \,a^{3} e}-\frac {\left (e^{2}\right )^{\frac {1}{4}} \sqrt {2}\, \arctan \left (-\frac {\sqrt {2}\, \sqrt {e \cot \left (d x +c \right )}}{\left (e^{2}\right )^{\frac {1}{4}}}+1\right )}{8 d \,a^{3} e}+\frac {\sqrt {2}\, \ln \left (\frac {e \cot \left (d x +c \right )-\left (e^{2}\right )^{\frac {1}{4}} \sqrt {e \cot \left (d x +c \right )}\, \sqrt {2}+\sqrt {e^{2}}}{e \cot \left (d x +c \right )+\left (e^{2}\right )^{\frac {1}{4}} \sqrt {e \cot \left (d x +c \right )}\, \sqrt {2}+\sqrt {e^{2}}}\right )}{16 d \,a^{3} \left (e^{2}\right )^{\frac {1}{4}}}+\frac {\sqrt {2}\, \arctan \left (\frac {\sqrt {2}\, \sqrt {e \cot \left (d x +c \right )}}{\left (e^{2}\right )^{\frac {1}{4}}}+1\right )}{8 d \,a^{3} \left (e^{2}\right )^{\frac {1}{4}}}-\frac {\sqrt {2}\, \arctan \left (-\frac {\sqrt {2}\, \sqrt {e \cot \left (d x +c \right )}}{\left (e^{2}\right )^{\frac {1}{4}}}+1\right )}{8 d \,a^{3} \left (e^{2}\right )^{\frac {1}{4}}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 0.51, size = 189, normalized size = 1.15 \[ -\frac {e {\left (\frac {9 \, e \sqrt {\frac {e}{\tan \left (d x + c\right )}} + 7 \, \left (\frac {e}{\tan \left (d x + c\right )}\right )^{\frac {3}{2}}}{a^{3} e^{3} + \frac {2 \, a^{3} e^{3}}{\tan \left (d x + c\right )} + \frac {a^{3} e^{3}}{\tan \left (d x + c\right )^{2}}} - \frac {2 \, {\left (\frac {\sqrt {2} \arctan \left (\frac {\sqrt {2} {\left (\sqrt {2} \sqrt {e} + 2 \, \sqrt {\frac {e}{\tan \left (d x + c\right )}}\right )}}{2 \, \sqrt {e}}\right )}{\sqrt {e}} + \frac {\sqrt {2} \arctan \left (-\frac {\sqrt {2} {\left (\sqrt {2} \sqrt {e} - 2 \, \sqrt {\frac {e}{\tan \left (d x + c\right )}}\right )}}{2 \, \sqrt {e}}\right )}{\sqrt {e}}\right )}}{a^{3} e} + \frac {11 \, \arctan \left (\frac {\sqrt {\frac {e}{\tan \left (d x + c\right )}}}{\sqrt {e}}\right )}{a^{3} e^{\frac {3}{2}}}\right )}}{8 \, d} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 0.94, size = 173, normalized size = 1.05 \[ \frac {\sqrt {2}\,\left (2\,\mathrm {atan}\left (\frac {\sqrt {2}\,\sqrt {e\,\mathrm {cot}\left (c+d\,x\right )}}{2\,\sqrt {e}}\right )+2\,\mathrm {atan}\left (\frac {\sqrt {2}\,\sqrt {e\,\mathrm {cot}\left (c+d\,x\right )}}{2\,\sqrt {e}}+\frac {\sqrt {2}\,{\left (e\,\mathrm {cot}\left (c+d\,x\right )\right )}^{3/2}}{2\,e^{3/2}}\right )\right )}{8\,a^3\,d\,\sqrt {e}}-\frac {11\,\mathrm {atan}\left (\frac {\sqrt {e\,\mathrm {cot}\left (c+d\,x\right )}}{\sqrt {e}}\right )}{8\,a^3\,d\,\sqrt {e}}-\frac {\frac {9\,e\,\sqrt {e\,\mathrm {cot}\left (c+d\,x\right )}}{8}+\frac {7\,{\left (e\,\mathrm {cot}\left (c+d\,x\right )\right )}^{3/2}}{8}}{d\,a^3\,e^2\,{\mathrm {cot}\left (c+d\,x\right )}^2+2\,d\,a^3\,e^2\,\mathrm {cot}\left (c+d\,x\right )+d\,a^3\,e^2} \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ \frac {\int \frac {1}{\sqrt {e \cot {\left (c + d x \right )}} \cot ^{3}{\left (c + d x \right )} + 3 \sqrt {e \cot {\left (c + d x \right )}} \cot ^{2}{\left (c + d x \right )} + 3 \sqrt {e \cot {\left (c + d x \right )}} \cot {\left (c + d x \right )} + \sqrt {e \cot {\left (c + d x \right )}}}\, dx}{a^{3}} \]
Verification of antiderivative is not currently implemented for this CAS.
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